Question

Two wires a and b of the same material having lengths in the ratio of 1:2 and the diameter are in the ratio 2:3 are connected in series with an accumulator . Compute the ratio of p.ds across the two wires

Answer 1

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Answer 2

Hey.
Since R =p l/A

so, r1/r2= pl/A / p2l/4A. .....as A= π(2d)^2
so, r1/r2=2

as V=IR
so, V1/V2 =Ir1/Ir2=r1/r2=2

Thanks.