Question

Two wires are held perpendicular to the plane
of paper and are 5 m apart. The currents of 2.5
A and 5 A in same dir Then, the magnetic field
strength (B) point midway between the wires
will be​

Answer 1

Explanation:

1st wire ,B1 = (10^-7 x 2x 2.5) / 2.5

= 2 x 10 ^-7 T

2nd wire ,B2 = ( 10^-7 x 2 x 5) / 2.5

= 4 x 10^-7 T

at the mid poin both the field are in opposite of direction.then,

B = B2 -B1 = 2 x 10^-7 T