Two wires are of equal length and the same material but their diameters are in the ratio 2:3. If resistance of first wire is 3.6 ohms, find the resistance of second wire.
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Answer:
R = ρl/πr 2 = ρl/π(d/2) 2 = 4ρl/πd 2
where R = resistance
ρ = resistivity or specific resistance.
l = length
r = radius.
d = diameter.
Thus resistance is inversely proportional to the square of the diameter.
It is given that lengths are equal.
R1 : R2 = d2 2 : d1 2
3.6/R2 = 9/4
R2 = (4 * 3.6)/9
R2 = 1.6 Ω
Explanation:
MARK BRAINLIEST
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