Question

Two wires each of length 44 CM are bent into a square and a circle respectively find the area of the square and the area of the circle

Answer 1

$\bigstar\large\bf{Area_{(circle)}\boxed{\leadsto 154\:cm^2}}$

$\bigstar\large\bf{Area_{(square)}\boxed{\leadsto 121\:cm^2}}$

______________________________________

$\large\bf\underline{Here,}$

• Length of wires = 44 cm
• The 2 wires are bent to form a square and a circle

$\large\bf\underline{For\: square:}$

❒ Perimeter of square is 44 cm ; if a is side of square ,

ㅤㅤㅤㅤㅤ$\large\bf{⟼side \:a = \frac{44}{4}cm}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼side=11\:cm}$

$\underline{\boxed{\large\bf\pink{area\:of\:square= side\times side}}}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼area=11\times 11}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼area=121\:cm^2}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼area=154\:cm^2}$

$\boxed{\large\bf\green{\leadsto area=121\:cm^2}}$

______________________________________

$\large\bf\underline{For\: circle:}$

❒ Perimeter of circle is 44 cm ; if r is radius of circle ,

ㅤㅤㅤㅤㅤ$\large\bf{⟼radius\:r= \frac{44}{2\pi}}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼radius\:r=\frac{44}{2}\times\frac{7}{22}}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼radius\:r=\frac{\cancel{44}}{\cancel{44}}\times 7}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼radius\:r=7\:cm}$

$\underline{\boxed{\large\bf\pink{area\:of\: circle=\pi r^2}}}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼area=\frac{22}{\cancel{7}}\times \cancel{7}\times 7}$

ㅤㅤㅤㅤㅤ$\large\bf{⟼area=154\:cm^2}$

$\boxed{\large\bf\green{\leadsto area=154\:cm^2}}$