Two wires have lengths, resistances,
resistivities-each in the ratio 1:2. What is
1!
the ratio of their diameters?
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Answer
R1=rho1×l1/A1
R2=rho2×l2/A2
Divide equations
R1/R2=((rho1×l1)/(rho2×l2))×(A2/A1)
1/2=(1÷4)×r2^2/r1^2
r1/r2=1/2^(1/2)
2×r1/2×r2=1/2^(1/2)
d1/d2=1/2^(1/2
Explanation:
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