Question

two wires have same terminal p.d. if ratio of current flowing throw them is 1:3. calculate the ratio of their resistance​

Answer 1

Explanation:

⇒R

1

:R

2

:R

3

=

A

1

L

1

:

A

2

L

2

:

A

3

L

3

=

A

1

1

:

2A

1

L

2

:

2

A

1

L

3

=1:

2

2

:

2

1

3

R

1

:R

2

:R

3

=1:1:6

As they are in parallel Iα

R

1

⇒I

1

:I

2

:I

3

=

R

1

1

:

R

2

1

:

R

3

1

=1:1:

6

1

=6:6:1

Power=VI⇒PαI

⇒P

1

:P

2

:P

3

=I

1

:I

2

:I

3

=6:6:1

Answer 2

Answer:

By ohm's law :R=V/I

I=V/R

For the first wire : I1 =V/R15

and for second wire : I2=V/R2

Given:

I1:I2=1:3

Therefore, I1/I2=V/R1×R2/V = R2/R1

=> 1/3=R2/R1

=> R1/R2= 3/1

Therefore, R1:R2=3:1