Question

Two wires of a given material have length L and nL while their areas of cross section are A and A/n^2. The ratio of young moduli, for the two wires would be
A) 1/n. B)1/n^3. C)n^3. 4)1

Answer 1

Answer D

Explanation:

Because both wires are of same material

Answer 2

Thus the ratio of Young's modulus between the two wires is 1 / n^3

Option (B) is correct.

Explanation:

We are given

Length = L and nL

Area =  A and A / n^2

The formula of young's modulus is given as:

Y = FL /A

Where

• F = force
• a = area
• L = length

F L / A : F n L / A^2 / n^2

L / A :  n.L / A^2

L/A : n.n^2.L / A

1 : n^3

Thus the ratio of Young's modulus between the two wires is 1 / n^3