Two wires of diameter 0.35 cm, one made of steel and the other made of brass are loaded as shown in the figure. The unloaded length of steel wire is 2.3m and that of brass wire is 2 m. Compute the elongations of the steel and the brass wires.
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Answered by
0
Explanation:
The elongation in the rope is:
δ
L
=
1.10
m
The mass of the man is:
m
=
65
k
g
The length of the rope is:
L
=
45
m
The diameter of the wire is:
d
=
7
m
m
=
7
×
10
−
3
m
The acceleration due to the gravity is:
g
=
9.81
m
/
s
2
The Young's modulus of the nylon rope is as follows:
E
=
4
m
g
L
π
d
2
δ
L
E
=
4
×
65
k
g
×
9.81
m
/
s
2
×
45
m
π
×
(
7
×
10
−
3
m
)
2
×
1.10
m
E
=
6.77
×
10
8
P
a
Thus, the Young's modulus of the nylon rope is
6.77
×
10
8
P
a
.
Answered by
1
Answer:
made of steel and the other made of brass are loaded as shown in the figure. The unloaded length of steel wire is 2.3m and that of brass wire is 2 m. Compute the elongations of the steel and the brass wires.
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