Two wires of different material have same length and area of cross-section. What is the ratio of their increase in length when forces applied are the same? (Y₁ = 0.9 × 10¹¹ N m⁻², Y₂ = 3.6 × 10¹¹ N m⁻²).
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4
Given, Two wires of different material have same length and cross sectional area e.g.,
and
and also 
,
we know, Young's modulus, Y = FL/A∆L
so, ∆L = FL/YA
A, F and L are constant.
e.g.,
= (3.6 × 10¹¹)/(0.9 × 10¹¹)
= 4/1
Hence, ratio of their increase in length = 4 : 1
we know, Young's modulus, Y = FL/A∆L
so, ∆L = FL/YA
A, F and L are constant.
e.g.,
= (3.6 × 10¹¹)/(0.9 × 10¹¹)
= 4/1
Hence, ratio of their increase in length = 4 : 1
Answered by
2
Explanation:
therefore ratio of increase in length is 4:1 hope, it will help you
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