Physics, asked by jaspreet14sidhu, 1 year ago

Two wires of equal diameters of resistivity p1 and p2 , length X1 and X2 respectively are joined in series . The equivalent resistivity of the combination is

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Answered by sona1859

3

p=RA/l so when we find equivalent resistivity we get p net = p1+p2= RA/L1+ RA/L2 =RA(1/X1+1/X2 )

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