Question

Two wires of equal length and cross sectional area are suspended as shown in figure. Their youngs modulus are Y1= 2×10^11 Pa and Y2=0.90×10^11Pa respectively. What will be the equivalent youngs modulus

Answer 1

Answer:

The answer will be 1.45 x 10^11 Pa

Explanation:

According to the figure we can see that the two wire of same length have the young modulus named Y1 and Y2

Let the equivalent modulus be Y

Therefore Y = Y1+Y2/2

                    = 2×10^11 +0.90×10^11 /2

                      = (2+0.90) x 10^11/2

                      = 1.45 x 10^11 Pa

Therefore the equivalent young modulus will be  1.45 x 10^11 Pa