Question

Two wires of equal length are stretched by the same force. One wire is heavy while the other is light which one will have less frequency
(A) heavier wire
(B) lighter wire
(C) both have same frequency
(D) data insufficient
​

Answer 1

Answer:

Correct option is

C

2:3

Y=

a△l

Fl

or △l∝

a

l

a=area,l=length of wires,△l=elongation in length

Since the material (means Y will be same for both), force and lengths are same. Thus ratio extensions will be inversely proportional to ratio of areas.

Now,

m

2

m

1

=

2

3

or

(Density×Volume)

2

(Density×Volume)

1

=

2

3

thus,

A

2

A

1

=

2

3

becauseVolume=Area×lengthandlengthissame.

Since areas are in ratio 3:2, thus extensions will be in ratio 2:3