two wires of length 42 CM are Bent to form a square and rectangle the breadth of the rectangle formed is 5 cm which of the following square and rectangle will have a great area and by how much
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length of the wire= 42 cm
since all the sides of square are equal in length
length of one side = 42/4=10.5 cm
and area of square is a²=(10.5)=110.25 cm²
now rectangle
breadth=5cm so length will be 42-5*2/2=16 cm
area =length *breadth
16*5=80 cm²
hope it helps
mark as brainliest
since all the sides of square are equal in length
length of one side = 42/4=10.5 cm
and area of square is a²=(10.5)=110.25 cm²
now rectangle
breadth=5cm so length will be 42-5*2/2=16 cm
area =length *breadth
16*5=80 cm²
hope it helps
mark as brainliest
poonam971:
thanks so much
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