Question

Two wires of length 44 cm are bent to form a square and a rectangle. The breadth of the rectangle
is 5 cm. Which of the two figures, square and rectangle will have a greater area and by how much?
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Answer 1

Answer:

36cm^(2)

Step-by-step explanation:

Area of square= a^(2)

The sides of square are equal. So, 44/4= 11cm

Area of square= 11cm×11cm

121cm^(2)

We have to find length if rectangle.

Perimeter of rectangle= 44cm

44cm= 2(l+b)

44cm= 2l+2b

44cm= 2l+2(5)cm

44cm= 2l+10cm

44cm-10cm= 2l

34cm= 2l

34cm/2= l

17cm= l

Area of rectangle= length×breadth

17cm×5cm= 85cm^(2)

121cm^(2)-85cm^(2)= 36cm^(2)

The square has more area by 36cm^(2)

Answer 2

Answer:

36cm²

Step-by-step explanation:

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