Question

TWO WIRES OF RESISTANCE 4 OHM AND 6 OHM CONNECTED IN PARALLEL TO A BATTERY OF EMF 6 VOLT AND INTERNAL RESISTANCE 1.6 OHM . CALCULATE THE AMOUNT OF HEAT ENERGY PRODUCED IN THE CIRCUIT .

Answer 1

Answer:

(a) V= 6V 

Req = 1/R1 + 1 /R2  = 1/4 + 1/6 = 5/12 = 12/5 ohm = 2.4 ohm

According to ohm's law ,

V = IR 

I = V/R 

I = 6/2.4

I = 2.5 A

(b)  1) V = 6 V  , R= 6 ohm , I = ?

I = V/R 

I = 6/6 

I = 1 A

2) V = 6V , R = 4 ohm , I = ?

I = V/R 

I = 6 /4 

I = 1.5 A 

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