Math, asked by saumyasingh77, 11 months ago

two wires of resistance R1 and R2 case equivalent resistance of 20 ohm and connected in parallel the equivalent resistance of 4.8 ohm calculate the value of R1 and R2​

Answers

Answered by krush51
0

Step-by-step explanation:

R1 + R2 = 20

(R1 . R2)/ R1 + R2 = 48/10

solve them simultaneously u will get answer

Answered by mahimaacs2002
2

Answer:

When resistors are connected in series, equivalent Resistance R ==>

R1 + R2

In parallel ==> 1/R = 1/R1 + 1/R2

So equivalent Resistance = (R1×R2)/(R1+R2)

Given:

R1+R2 = 20 ohm

(R1×R2) / R1+R2 = 4.8 ohm

(R1×R2) / 20 = 4.8

R1×R2 = 96

R2=96/R1 --(1)

From R1 + R2 = 20

R1 + 96/R1 = 20

R1^2 - 20R1 + 96 = 0

R1^2 -12R1 - 8R1 + 96 =0

R1(R1 -12) -8(R1 - 12) = 0

(R1 - 12)(R1 - 8) = 0

So its 8 and 12

Similar questions