Question

two wires of resistance R1 and R2 case equivalent resistance of 20 ohm and connected in parallel the equivalent resistance of 4.8 ohm calculate the value of R1 and R2​

Answer 1

Step-by-step explanation:

R1 + R2 = 20

(R1 . R2)/ R1 + R2 = 48/10

solve them simultaneously u will get answer

Answer 2

Answer:

When resistors are connected in series, equivalent Resistance R ==>

R1 + R2

In parallel ==> 1/R = 1/R1 + 1/R2

So equivalent Resistance = (R1×R2)/(R1+R2)

Given:

R1+R2 = 20 ohm

(R1×R2) / R1+R2 = 4.8 ohm

(R1×R2) / 20 = 4.8

R1×R2 = 96

R2=96/R1 --(1)

From R1 + R2 = 20

R1 + 96/R1 = 20

R1^2 - 20R1 + 96 = 0

R1^2 -12R1 - 8R1 + 96 =0

R1(R1 -12) -8(R1 - 12) = 0

(R1 - 12)(R1 - 8) = 0

So its 8 and 12