Two wires of same diameter of the same material having the length l and 2l
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Answer:
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Explanation:
Answered by
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Answer: 1:8
Explanation:. Resistance for a material
R varies length(l)
R varies 1/area(A)
Hence R=constant ×l/A
Constant depends on the material. Let it be k.
R1=(k1×l)/(π×r^2)
R2=(k2×2l)/[π×(r/2)^2]
R2=k2×8l/πr^2
R1:R2=k1×l/πr^2:k2×8l/πr^2
Since the material is same ..so k1=k2
R1:R2= 1:8
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