two wires of same length and area made of two materials of resistivity P1 and P2 are connected in series of potential V. The equivalent resistivity for the same area is
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Answer:
(P1 + P2)/2
Explanation:
R1 = P1 l/a
R2 = P2l/a
R(EQUI) = R1+R2
= l/a(P1 + P2)
P(EQUI)2l/a = l/a (P1+P2)
P(EQUI) =( P1 +P2)/2
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