Two wires of same material and length but cross-sections in the ratio 1 : 2 are used to suspend the same loads. The extensions in them will be in the ratio (a) 1 : 2 (b) 2 : 1 (c) 4 : 1 (d) 1 : 4
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Let the cross section of wire be A , 2A
ΔL1 = Fl/AY
ΔL2 = 2AY/Fl
so, ΔL1/Δ2 = 2/1
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