Physics, asked by queena540, 10 months ago

Two wires of same material and length but cross-sections in the ratio 1 : 2 are used to suspend the same loads. The extensions in them will be in the ratio (a) 1 : 2 (b) 2 : 1 (c) 4 : 1 (d) 1 : 4

Answers

Answered by educationtech
2

Answer:

Let the cross section of wire be A , 2A

ΔL1 = Fl/AY

ΔL2 = 2AY/Fl

so, ΔL1/Δ2 = 2/1

I think it's help you

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