Question

Two wires of same material and same area of cross section are of lengths L and 2L. they are stretched by the same force F along the length. the ratio of the strains produced in them will be:​

Answer 1

Answer:

Correct option is D)

∵ Both wires are same materials so both will have same Young's modulus, and let it be Y

Y=

strain

stress

=

A(ΔL/L)

F

Here, F= applied force and A= area of cross-section of wire

Now, Y

1

=Y

2

⇒

(A

1

)(ΔL

1

)

FL

=

(A

2

)(ΔL

2

)

FL

Since load and length are same for both

⇒r

1

2

ΔL

1

=r

2

2

ΔL

2

, [

ΔL

2

ΔL

1

]=[

r

1

r

2

]

2

=4

ΔL

1

:ΔL

2

=4:1