Two wires of Same material have length in ratio 1:2. the ratio of specific resistance will be
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Answered by
5
we know that ,the wires are made up of same material , hence resistivity will be same , and as it is a series combination so current will be same .
Here, we have L1 : L2 = 1:2
and, d1: d2= 2:3 (YOU NOT MENTIONED )
therefore , with the help of ohms law
v = IR
where, v = potential difference
I= current
and R= resistance.
also , R=p ౹ / A
so, v = ౹ p౹ /A
here, p= resistivity of conductor, l= length of conductor, A = area of cross section of conductor.
For the two wires,
therefore, the lengths are l1 , l2
for the cross section areas A1, A2
and for the diameters D1, D2
now follow the picture,
Here, we have L1 : L2 = 1:2
and, d1: d2= 2:3 (YOU NOT MENTIONED )
therefore , with the help of ohms law
v = IR
where, v = potential difference
I= current
and R= resistance.
also , R=p ౹ / A
so, v = ౹ p౹ /A
here, p= resistivity of conductor, l= length of conductor, A = area of cross section of conductor.
For the two wires,
therefore, the lengths are l1 , l2
for the cross section areas A1, A2
and for the diameters D1, D2
now follow the picture,
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Answered by
13
if wires form with same material then , specific resistance is same , bcoz this depends upon only material . not length of wire
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