two wires of same material have length L and 3L and cross sectional area 4A and A respectively. the ratio of their specific resistance would be
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Explanation:
As R=
A
ρl
R∝
A
l
R
2
R
1
=
A
1
l
1
×
l
2
A
2
R
2
R
1
=
4A
L
×
2L
A
=1:8
⎣
⎢
⎢
⎢
⎢
⎡
l
1
=L
l
2
=2L
A
1
=4A
A
2
=A
⎦
⎥
⎥
⎥
⎥
⎤
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