Two wires of same material having length in the ratio 1 is to do and die metres in the ratio of
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1) We know that the Resistance of a same wire is proportional to (l/A) .
where L = Length of wire,
A = Area of cross section
And, Area is proportional to d^2 ,
where 'd' is diameter of wire.
=> Resistance is proportional to
2) We have,
Ratio of their length = 1:2
Ratio of diameters = 2:3
=> Ratio of Area of cross- section = 2^2:3^2 = 4:9
=> Ratio of resistance :
9:16
3) Since, current in series circuit is same.
=> Ratio of Potential difference across wires :
R(1) : R(2) = 9:16
1) We know that the Resistance of a same wire is proportional to (l/A) .
where L = Length of wire,
A = Area of cross section
And, Area is proportional to d^2 ,
where 'd' is diameter of wire.
=> Resistance is proportional to
2) We have,
Ratio of their length = 1:2
Ratio of diameters = 2:3
=> Ratio of Area of cross- section = 2^2:3^2 = 4:9
=> Ratio of resistance :
9:16
3) Since, current in series circuit is same.
=> Ratio of Potential difference across wires :
R(1) : R(2) = 9:16
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