Question

Two wires of same metal have a same length but the cross section is in ratio 3:1. they re joined in series. The resistance of the thicker wire is 10Ω. The total resistance of the combination will be

Answer 1

Answer:

40 ohm

Explanation:

resistence of wire A =10 ohm.

therefore resistence of thinner wire=3*10=30 ohm. (R=pl/A)

total R = 10+30=40 ohm..(since they are in series)

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