Two wires of same thickness and made of same material have lengths 1m and 2m respectively out of these 2 wire, which will have more resistance? Why?
Answers
Answer:
The electrical resistance of a circuit component or device is defined as the ratio of the voltage applied to the electric current whichflows through it. That is R=V/I.
The electrical resistance of a wire would be expected to be greater for a longer wire, less for a wire of larger cross sectional area (that is square of the radius), and would be expected to depend upon the material out of which the wire is made.
The resistance of a wire can be expressed as R=
A
ρL
where,
rho is the resistivity of the wire,
L is the length of the wire,
A is the area of cross section of the wire, that is, square of the radius.
In this case, two wires of the same material and same length have radii r1 and r2 respectively are taken. So, the resistance will differ only in the square of the radius.
Hence, the ratio of the resistance would be r
1
2
:r
2
2
and 1:1.
Answer:
the longer material will have more resistance.
Explanation:
length of first wire=1
length of second wire=2
Resistivity
=length/area of cross section * specific resistivity of material
first wire= 1/a*r
second wire= 2/a*r
as area of cross section and material are same so we can take them as x,
thus,
Resistivity of first wire= 1x
Resistivity of second wire=2x
hence the resistivity of second wire is more