Two wires of smae material are having lengths in the ratio 2:3 and radii 1:2 find the ratio of their resistances
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R is directly promotion to length and indirectly proportional to area. So
R1=l1/a1
R2=l2/a2
If l1/l2=2/3 then l1=2/3 l2
And a1/a2=(1/2)^2 ( a=πr^2) so a1=a2/4
R1=2/3 l2 / (a2 /4)
L2/a2=r2 solve to get ratio
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