Question

two wires of some material and same cross section are stretched out one wire is loaded with 1.5kg and another is loaded with 6 kg vibrating length of 1st is 60 cm and fundamental frequency of both wire is same calculate vibrating length of other wire​

Answer 1

Answer:

fundamental frequency f=  

2l  

1

​  

 

1

​  

 

μ

T  

1

​  

 

​  

 

​  

 

first over tone f  

′

 

=  

2l  

2

​  

 

2

​  

 

μ

T  

2

​  

 

​  

 

​  

 

given f=  

2l

1

​  

 

μ

12

​  

 

​  

=  

2l  

1

​  

 

2

​  

 

μ

3

​  

 

​  

 

f  

′

 

=  

2l  

2

​  

 

2

​  

 

μ

3

​  

 

​  

 

∴f  

′

 

=f  ⇒l  

1

​  

=l  

2

​  

=100 cm

Explanation: