two wires of the same material and same length have radii 1 mm and 2 mm respectively compare first the resistances, the specific resistance
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Given : Two wires of the same material and same length have radii 1mm and 2mm respectively.
To find : ratio of their resistances and their specific resistances.
solution : we know, R = ρL/A
where ρ is specific resistance of material.
as A = πr²
so, R = ρL/πr²
here material and length of wires are same so, R ∝ 1/r².
i.e., R₁/R₂ = (r₂/r₁)² = (2mm/1mm)² = 4 : 1
Therefore the ratio of their resistances is 4 : 1
as two wires are made of the same material, so specific resistances of both wires are same.
Therefore the ratio of their specific resistances is 1 : 1
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