Two wires of the same metal have the same length, but cross section are in the ratio 3:1. The are in joined in series. The resistance of thicker wire is 10 ohm.The total resistance of the combined will be
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hi!!!
resistance of wire A = 10 ohm.
therefore resistance of thinner wire = 3 × 10 = 30 ohm. (R = pl/A)
total R = 10 + 30 = 40 ohm... (since they are in series)
hope it helps✌️✌️
resistance of wire A = 10 ohm.
therefore resistance of thinner wire = 3 × 10 = 30 ohm. (R = pl/A)
total R = 10 + 30 = 40 ohm... (since they are in series)
hope it helps✌️✌️
DKanchu:
thanks for your ans
YO✌✌
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