Math, asked by aarus6730, 1 year ago

Two wires , one of copper and other of manganin, have equal lengths and equal resistances. which wire is thicker given that resistivity of copper is lower than that of mangarin

Answers

Answered by Anonymous
5
R=ρlAR=ρlA=>A∞ρ=>A∞ρ
if l and R are constant
But ρρ is greater for manganin than copper, therefore manganin wire is thicker than copper wire .
Answered by Atharv3812
1

We know that resistance of a wire is given as,

R = ρL/A

let the resistivity and area of copper wire is ρ₁ and A₁

and let the resistivity and area of manganin wire is ρ₂ and A₂

since resistance and length of both the wires are equal,

=> ρ₁/A₁ = ρ₂/A₂

=> A₁/A₂ = ρ₁/ρ₂

since ρ₁<ρ₂

=> A₁<A₂

hence manganin wire will be more thicker.

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