Two wires , one of copper and other of manganin, have equal lengths and equal resistances. which wire is thicker given that resistivity of copper is lower than that of mangarin
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R=ρlAR=ρlA=>A∞ρ=>A∞ρ
if l and R are constant
But ρρ is greater for manganin than copper, therefore manganin wire is thicker than copper wire .
if l and R are constant
But ρρ is greater for manganin than copper, therefore manganin wire is thicker than copper wire .
Answered by
1
We know that resistance of a wire is given as,
R = ρL/A
let the resistivity and area of copper wire is ρ₁ and A₁
and let the resistivity and area of manganin wire is ρ₂ and A₂
since resistance and length of both the wires are equal,
=> ρ₁/A₁ = ρ₂/A₂
=> A₁/A₂ = ρ₁/ρ₂
since ρ₁<ρ₂
=> A₁<A₂
hence manganin wire will be more thicker.
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