Question

two wires,one of copper and other of manganin, have equal lengths and equal resistances.Which wire is thicker ?Given that resistivity of copper is lower than that of manganin

Answer 1

R = p l / a

Here p = resistivity .

l = length .

a = area of cross section .

R = resistance .

Resistances of the wires are same .

Length is same .

Resistivity of copper < resistivity of manganin .

R = p l / a

= > R a = p l

= > a = p l / R

Thickness of area of cross section is directly proportional to resistivity .

Since mangnain has more resistivity , the thickness will also be more .

ANSWER :

Manganin

Answer 2

We know that resistance of a wire is given as,

R = ρL/A

let the resistivity and area of copper wire is ρ₁ and A₁

and let the resistivity and area of manganin wire is ρ₂ and A₂

since resistance and length of both the wires are equal,

=> ρ₁/A₁ = ρ₂/A₂

=> A₁/A₂ = ρ₁/ρ₂

since ρ₁<ρ₂

=> A₁<A₂

hence manganin wire will be more thicker.

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