Two wires P and Q of same diameter and same length are joined in parrallel and combination is connected across a battery. The resistance of P i.e Rp is greater than the resistance of Q i.e Rq. Which wire will become hottar. 2marks
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The wire Q will become hotter.
Given:
Two wires P and Q
Length and diameter are the same for wire P and Q.
Rp is greater than Rq
To Find:
Which wire will become hotter?
Solution:
We know more the power is dissipated more it becomes hotter.
P = V²/R (for parallel combination)
From the above formula, Power is inversely proportional to the resistance of a wire.
So, When the resistance is more, the lesser the power dissipated thereby lesser it will become hotter
Therefore, The wire Q will become hotter.
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