Two wires, X and Y, are made from different metals and have different dimensions. The Young modulus of wire X is twice that of wire Y. The diameter of wire X is half that of wire Y. Both wires are extended with equal strain and obey Hooke’s law. What is the ratio Y wirein tension tension in wire X ? A 1/8 B1/ 2 C 1 D 8
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Yx= 2Yy ........Y-oungs modulus
Dx = 1/2 Dy ..............D- diameter
e/L- strain
Tx/ Ty =[ Yx * pi Dx^2 /4 e / L] /[ Yy * pi Dy ^2/ 4 *e /L ]
= Yx Dx^2 / Yy Dy^2
= Yx * Dx^2 / 1/2Yx. 4Dx^2
= 1/ (1/2 *4)
= 1/2
note :- Y = (T/A) / (e/L)
A = pi d^2 /4
hope this help you
Dx = 1/2 Dy ..............D- diameter
e/L- strain
Tx/ Ty =[ Yx * pi Dx^2 /4 e / L] /[ Yy * pi Dy ^2/ 4 *e /L ]
= Yx Dx^2 / Yy Dy^2
= Yx * Dx^2 / 1/2Yx. 4Dx^2
= 1/ (1/2 *4)
= 1/2
note :- Y = (T/A) / (e/L)
A = pi d^2 /4
hope this help you
elumalaisrilakp4z4h3:
thank you so much bro... : )
wlcm
Answered by
16
The ratio of tension in wire X to the tension in wire Y is 1/2.
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thank you so much for taking the time to write everything so clearly and comprehensibly!!!!!
No problem... It helped in my practice too..
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