Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together .If B worked alone, he would need 9/2 hours more to complete the job than they both working together. what time would they take to do the work together
Answers
Answered by
8
answer:-
1/x+8 + 1/x+4.5 = 1/x
1/x+4.5 = 1/x - 1/x+8
1/x+4.5 = x+8-x/(x(x+8)
1/x+4.5 = 8/(x(x+8)
x(x+8) = 8(x+4.5)
x² + 8x = 8(x+4.5)
x² = 40
x is equal to approximately 6.
anildeshmukh:
;)
Answered by
0
Answer:
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Step-by-step explanation:
1/x+8 + 1/x+4.5 = 1/x
1/x+4.5 = 1/x - 1/x+8
1/x+4.5 = x+8-x/(x(x+8)
1/x+4.5 = 8/(x(x+8)
x(x+8) = 8(x+4.5)
x² + 8x = 8(x+4.5)
x² = 40
x is equal to approximately 6.
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