Math, asked by valenzuelafritz6, 6 months ago

two workers A and B together can complete a job in 7 days. A works twice as fast as B. How many days would it take B to do the job working alone?

Answers

Answered by OmRajeDongare
0

Answer:

Step-by-step explanation:

Let us assume A’s effort for the work is x (per day) ,

As, A works twice as fast as B, so, B’s effort for the work is 0.5x (per day)

Thus , in a day both A & B spend 1.5x amount of effort.

They complete the task in 8 days, tat means the total amount of effort spend by both working together is 1.5x*8 = 12x

By this we can conclude that this job need 12x amount of effort to be completed

As, a provides x amount of effort per day, it will require 12 days to complete the job.

Thanks

Answered by Urych
0

Answer:

21

Step-by-step explanation:

1/7 = 1/0.5x +1/x

1/7 = 3/x

x = 21

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