Question

two workers A and B together can finish a work in 8 days they worked together for 6 days and a left the work the remaining work was completed by b alone in 6 days how many days code each day take to complete the work individually​

Answer 1

Solution:-

Let A takes 'x' time to complete the work alone.

So, one day work of A = 1/x

And,

Let B takes 'y' time to complete the work alone.

So, one day work of B = 1/y

One day work of both A and B when they work together = 1/8

Now, 

⇒ 1/x + 1/y = 1/8

They work together for 6 days and A left. That means 6/8 work had already been completed.

So, remaining work = 1 - 6/8

= 2/8 

= 1/4

So, 1/4th part of total work is still remaining and B finished this 1/4th part in 6 days.

⇒ 6(1/y) = 1/4

⇒ 6/y = 1/4

⇒ y = 24

Hence B will take 24 days to complete the work alone.

Now,

Substituting the value of y = 24, we can have the value of x.

1/x + 1/y = 1/8

⇒ 1/x + 1/24 = 1/8

⇒ 1/x = 1/8 - 1/24

⇒ 1/x = 2/24

⇒ 1/x = 1/12

⇒ x = 12 

So, A will take 12 days to complete the work alone.

Answer 2

Worker a completes work in x days

He will complete work in one day = 1/x

Women completes a work in y days

She will complete work in 1 day = 1/y

Together they complete work in 8 days

Then work in 1 day = 1/8

Form equation
1/x + 1/y = 1/8

Solve equation and get answer