Two workers a and b working together completed a job in 5 days. if a had worked twice as efficiently as he actually did, the work would have been completed in 3 days. to complete the job alone, a would require
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One Day's work of A and B together,
1/A + 1/B = 1/5. ------ (i)
When A works with twice efficiency, Then,
2/A + 1/3B = 1/3. --------(ii)
on solving equations (i) and (ii), we get
A = 25/4 = 6(1/4).
1/A + 1/B = 1/5. ------ (i)
When A works with twice efficiency, Then,
2/A + 1/3B = 1/3. --------(ii)
on solving equations (i) and (ii), we get
A = 25/4 = 6(1/4).
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