Question

Two workers are sliding 360 kg crate across the floor. One worker pushes forward on the crate with a force of 450 n while the other pulls in the same direction with a force of 230 n using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?

Answer 1

Answer:

0.192

Explanation:

Total force in positive X d/c =680 N

Force due to friction in opposite direction= uN

,where N=360x9.8=3528N

If a=0,

u=[680/3528]=0.192