Two X plus one divided by X whole cube equal to
Answers
Answered by
1
Answer:
The answer is zero
(x+1/x)^2 =3
Taking root on both side that makes
(x+1/x)=√3……case 1
Now lets take cube on both side
(x+1/x)^3=(√3)^3
x^3 +1/x^3 + 3*x^2*1/x + 3*x*1/x^2=3*√3
x^3 + 1/x^3 + 3*x+ 3*1/x=3*√3
x^3 + 1/x^3+3*(x+1/x)=3*√3
From case 1 we know that x+1/x =√3
Therefore replacing x+1/x in equation we get
x^3 + 1/x^3 + 3*(√3)=3*√3
Taking 3*√3 on right side we get
x^3 + 1/x^3 = 3√3 - 3√3
Answered by
1
Answer:
Step-by-step explanation:
Given :
Two X plus one divided by X whole cube equal to
To find :
divided by X whole cube equal to
Solution :
x = 2-√3--(1)
1/x = 1/(2-√3) = (2+√3)/ [(2-√3)(2+√3)] = (2+√3)/[2²-(√3)²]
= (2+√3)/ (4-3)
= 2 + √3 ----(2)
x - 1/x
= 2-√3-(2 + √3)
= 2√3-2-√3
=-2√3---(3) =_
Then,
(x - 1/x)³ = (-2√3)³
= -24√3
Similar questions