Math, asked by drreddy18, 2 days ago

Two X plus one divided by X whole cube equal to

Answers

Answered by suryanshsharma2613
1

Answer:

The answer is zero

(x+1/x)^2 =3

Taking root on both side that makes

(x+1/x)=√3……case 1

Now lets take cube on both side

(x+1/x)^3=(√3)^3

x^3 +1/x^3 + 3*x^2*1/x + 3*x*1/x^2=3*√3

x^3 + 1/x^3 + 3*x+ 3*1/x=3*√3

x^3 + 1/x^3+3*(x+1/x)=3*√3

From case 1 we know that x+1/x =√3

Therefore replacing x+1/x in equation we get

x^3 + 1/x^3 + 3*(√3)=3*√3

Taking 3*√3 on right side we get

x^3 + 1/x^3 = 3√3 - 3√3

Answered by 7esuryanshumohansing
1

Answer:

Step-by-step explanation:

Given :

Two X plus one divided by X whole cube equal to

To find :

divided by X whole cube equal to

Solution :

x = 2-√3--(1)

1/x = 1/(2-√3) = (2+√3)/ [(2-√3)(2+√3)] = (2+√3)/[2²-(√3)²]

= (2+√3)/ (4-3)

= 2 + √3 ----(2)

x - 1/x

= 2-√3-(2 + √3)

= 2√3-2-√3

=-2√3---(3) =_

Then,

(x - 1/x)³ = (-2√3)³

= -24√3

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