Math, asked by pranavrane583, 9 months ago

two y square + 27 Y + 13 isequal to zero by factorization method​

Answers

Answered by Vamprixussa
10

Given equation

2y^{2} + 27y + 13 = 0

Solving, we get,

2y^{2} +27y+13=0\\

\implies 2y^{2} + y + 26y+13=0

\implies y(2y+1)+13(2y+1)=0

\implies (y+13)(2y+1)=0

Now,

y + 13 = 0\\\implies y = -13

2y+1 = 0\\\implies y = \dfrac{-1}{2}

\boxed{\boxed{\bold{Therefore \ the \ factorised \ expression \ is \ (y+13)(2y+1)}}}}

                                                         

Answered by Saby123
24

..- ...

 \tt{\huge{\purple{ ................. }}}

QUESTION -

two y square + 27 Y + 13 isequal to zero by factorization method...

SOLUTION -

 \tt{ \purple{ \leadsto{2 {y}^{2} + 2 7y + 13 = 0}}}

 \tt{ \blue{ \leadsto{2 {y}^{2} + 2 6y + y + 13 = 0}}}

 \tt{ \green{ \leadsto{2 y(y + 13) + 1(y + 13 )= 0}}}

 \sf{ \orange{ \mapsto{(2y + 1)(y + 13) = 0}}}

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