Question

two y square + 27 Y + 13 isequal to zero by factorization method​

Answer 1

Given equation

$2y^{2} + 27y + 13 = 0$

Solving, we get,

$2y^{2} +27y+13=0$

$\implies 2y^{2} + y + 26y+13=0$

$\implies y(2y+1)+13(2y+1)=0$

$\implies (y+13)(2y+1)=0$

Now,

$y + 13 = 0\\\implies y = -13$

$2y+1 = 0\\\implies y = \dfrac{-1}{2}$

$\boxed{\boxed{\bold{Therefore \ the \ factorised \ expression \ is \ (y+13)(2y+1)}}}}$

                                                         

Answer 2

..- ...

$\tt{\huge{\purple{ ................. }}}$

QUESTION -

two y square + 27 Y + 13 isequal to zero by factorization method...

SOLUTION -

$\tt{ \purple{ \leadsto{2 {y}^{2} + 2 7y + 13 = 0}}}$

$\tt{ \blue{ \leadsto{2 {y}^{2} + 2 6y + y + 13 = 0}}}$

$\tt{ \green{ \leadsto{2 y(y + 13) + 1(y + 13 )= 0}}}$

$\sf{ \orange{ \mapsto{(2y + 1)(y + 13) = 0}}}$