two year ago a father was three times as old as his son.two year hence, twice his age will be equal to five times his son's age .find their present ages
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let the age of father be x
and of son be y
then
2-x=3(2-y)
2-x=6-3y
2-6=x-3y
x-3y+4=0...(1)
and
2+x=2{5(2+y)}
2+x=2(10+5y)
2+x=20+10y
2-20=10y-x
x-10y+18=0.....(2)
by solving (1) @ (2)
we will get the values of x and y
and of son be y
then
2-x=3(2-y)
2-x=6-3y
2-6=x-3y
x-3y+4=0...(1)
and
2+x=2{5(2+y)}
2+x=2(10+5y)
2+x=20+10y
2-20=10y-x
x-10y+18=0.....(2)
by solving (1) @ (2)
we will get the values of x and y
mathsteacher:
answer is 38 yr n 14 year
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