Question

Two year ago father. Was three times as old as his son and two year hence twice his age will equal to five times of that of his son find prasent age

Answer 1

Answer:

x=38

y=14

Step-by-step explanation:

Let the age of father be=x

Age of son=y

Two years ago:-

x-2=3(y-2)

x-2=3y-6

3y-x=4→α

Two years hence:-

2(x+2)=5(y+2)

2x+4=5y+10

5y-2x=-6→β

2α-β→6y-2x=8

(-)       5y-2x=-6

y=14

3y-x=4

[3x14]-x=4

42-4=x

x=38