Question

Two year ago father was three times as old as his son and two year hence twice his age will be equal to five times that of his son. The present age of father and his son are​

Answer 1

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Answer 2

Answer:

Two years ago, Let the age of father be f years

and the age of son be s years

A/q

f= 3s

and , 2(f+4) = 5(s+4)

putting f= 3s

⇒2(3s+4) = 5(s+4)

⇒6s +8 = 5s +20

⇒s = 12

so present age of son = 14 years

and present age of father = 12×3 +2 = 38 years