Question

two year ago my age was 4.5 times of my son six years ago my age was twise the spuare of the age of my son . what is the present age of my son​

Answer 1

Answer:

It is given that my age was twice the square of the age of my son. y = 4.25 is discarded as age cannot be fractional. So, present age of son is y = 10 years.

Step-by-step explanation:

Let 2 years ago, son's age be x.

So my age(2 years ago) =4.5 x

So, 6 years ago,

My age=4.5x-4

Son's age=x-4

B/C,

4.5x-4=2((x-4)^2)

or, 4x^2–41x+72=0

Solving the quadratic, we get-

x=8 or x=2.5(not possible)

So my present age of=4.5x+2=38

My son's present age=x+2=10.(Ans)

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