Question

two year later a father will be eight year more then three times the age of the son . taking the present age of father and son as x and y respectively. a.: from the graph find the age of father when sons age is 10 year.​

Answer 1

Answer:

Step-by-step explanation:

Present:

Let the father's age be x

Let the son's age be y

Two years later:

The father's age x + 2

The son's age y + 2

Finding their present ages:

x + 2 =  3(y + 2) + 8

x + 2 = 3y + 6 + 8

x - 3y = 12

Plot it on the graph

Draw a parallel line thru the x-axis

Mark the point where it meets the line

Draw a perpendicular line from that point to meet the x-axis

Thus it meets the x axis

x = 42

The age of the father is 42 when the child is 10 years old.

Hope this helps:)