Question

two years ago a father was 3 times as old as his son and 2 year hence twice his age will be equal to 5 times that of his son .find the present age

Answer 1

Answer:

Father : 38 years

Son : 14 years

Step-by-step explanation:

• Let the Present age of Father be "x"

• Let the Present age of Son be "y"

• 2 Years ago:

x-2 = 3(y-2)

On further simplification, we'll get x = 3y - 4.....(1)

• 2 Years hence (Means two years after the present ages) :

(x + 2)*2 = 5 * (y + 2)

2x + 4 = 5y + 10

On further simplification, we'll get:

x = (5y + 6) / 2.......(2)

Equate eqn.1 and eqn.2

Now, We'll get:

• 3y - 4 = (5y + 6) / 2
• Multiplying 2 on both sides:

6y - 8 = 5y + 6

Therefore, Y = 14

Substitute Y = 14 in equation (1)

Therefore, x = (3* 14) - 4

Therefore, x = 42 - 4

Therefore, present age of father =38 yrs and present age of son = 14 yrs