Two years ago, a father was 5 times as old as his son . Two years later , his age will be 8 more than 3 times the age of the son. Find the present ages of father and son.
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let the father's age be f and the son's age be s
f-2=5(s-2)⇒f=5s-8......(i)
f+2=8+3(s+2)
putting eq(i)
5s-8+2=8+3s+6
⇒5s-6=3s+14
⇒2s=20 ⇒s=10
so the present age of the son is 10 yrs and the father's age is 42
f-2=5(s-2)⇒f=5s-8......(i)
f+2=8+3(s+2)
putting eq(i)
5s-8+2=8+3s+6
⇒5s-6=3s+14
⇒2s=20 ⇒s=10
so the present age of the son is 10 yrs and the father's age is 42
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