Question

Two years ago, a father was five times as old as his son . After two years his age will be 8 more than three times the age of his son . Find the present age of the father​

Answer 1

Answer:

Hey mate! Present age of father is 42 years.

Step-by-step explanation:

Let the ages of son and father, 2 years ago, be x and 5x.

Present age of son = x+2

Present age of father = 5x+2

After 2 years,

Age of son = x+4

Age of father = 5x+4

A/Q,

5x+4 = 3(x+4)+8

5x+4 = 3x+12+8

5x+4 = 3x+20

5x-3x = 20-4

2x = 16

x = 16/2

x = 8

Now,

Present age of father = 5x+2 = 5×8+2 = 40+2 = 42 years

Mark me as BRAINLIEST...

Answer 2

Answer:

your answer is here buddy

Step-by-step explanation:

father's present age is 42 and son's is 10

I HOPE IT'S HELP YOU ❤️