Question

Two years ago a father was five times as old as his son. Two years later his age will be 8 more than three times the age of the son find the present age of father and son

Answer 1

Answer:

present age of father is 42 and that of his son is 10

Step-by-step explanation:

let the present age of father be X

let the present age of son be y

therefore, 2 years ago

x-2 = 5× (y-2)

x = 5y - 8

number this as equation (1)

now, 2 years later

X+2= 8+ 5×(y+2)

X= 3y+2

number this as equation (2)

equate both equations

5y-8= 3y+12

where y = 10

and substitute y in eq (2)

we get X as 42