two years ago,a father was five times as old as his son. Two years later,his age will be 8 years more than three times the age of the son.Find the present ages of the father and the son.
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Answer:
Father's present age is 32 and son's present age is 8.
Step-by-step explanation:
1) two years ago,a father was five times as old as his son:
f - 2 = 5(s-2) ⇔ f - 2 = 5s - 10
2) two years later,his age will be 8 years more than three times the age of the son:
f = 3s + 8
Subtract the 2nd equation from the 1st one:
f - 2 - f = 5s - 10 - (3s + 8) ⇔ -2 = 2s - 18 ⇔ 16 = 2s ⇔ s = 8
Now, from equation 2:
f = 3s +8 = 3 * 8 + 8 = 32
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